Bond length between carbon-carbon in ethylene molecule is

Options

A. 1.54 Å
B. 1.35 Å
C. 1.19 Å
D. 2.4 Å

Answer

To determine the bond length between carbon-carbon in an ethylene molecule, we can follow these steps:

### Step 1: Understand the Structure of Ethylene
Ethylene (C2H4) is a hydrocarbon that consists of two carbon atoms connected by a double bond. The structure can be represented as H2C=CH2.

### Step 2: Identify the Bond Lengths
- The bond length for a carbon-carbon single bond (C-C) is approximately 154 picometers (pm).
- The bond length for a carbon-carbon double bond (C=C) is approximately 134 picometers (pm).
- The bond length for a carbon-carbon triple bond (C≡C) is approximately 120 picometers (pm).

### Step 3: Convert Picometers to Angstroms
We need to convert the bond length of the carbon-carbon double bond from picometers to angstroms. The conversion factor is:
1 picometer = 0.01 angstroms.

### Step 4: Calculate the Bond Length in Angstroms
To convert the bond length of the double bond (134 pm) to angstroms:
\[ \text{Bond length in angstroms} = 134 \, \text{pm} \times 0.01 \, \text{angstroms/pm} = 1.34 \, \text{angstroms} \]

### Step 5: Round the Result
When rounding 1.34 angstroms, we can approximate it to 1.35 angstroms, which is a common practice in reporting measurements.

### Conclusion
Therefore, the bond length between carbon-carbon in an ethylene molecule is approximately **1.35 angstroms**.

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