Home
Class 12
CHEMISTRY
Addition of HCl does not obey anti-Marko...

Addition of HCl does not obey anti-Markovnikov's rule because

A

It is a strong acid

B

It is a gas

C

Its bond energy is high

D

Its bond energy is less

Text Solution

AI Generated Solution

The correct Answer is:
**Step-by-Step Solution:** 1. **Understanding Anti-Markovnikov's Rule**: Anti-Markovnikov's rule states that in the addition of HX (where X is a halogen) to alkenes, the halogen atom (X) adds to the less substituted carbon atom of the double bond when free radicals are involved. This typically occurs in the presence of peroxides (like H2O2). 2. **Identifying the Reaction with HCl**: The question specifically mentions the addition of HCl to alkenes. HCl does not follow the anti-Markovnikov's rule because it does not generate free radicals in the reaction. 3. **Role of Free Radicals**: In reactions that follow anti-Markovnikov's rule, free radicals are generated, which allows for the halogen to attach to the less substituted carbon. However, this is not the case with HCl. 4. **High Bond Energy of HCl**: The bond energy of HCl is relatively high. This means that breaking the H-Cl bond to generate free radicals requires a significant amount of energy. As a result, HCl does not readily form free radicals under normal conditions. 5. **Conclusion**: Since HCl does not generate free radicals due to its high bond energy, it does not obey the anti-Markovnikov's rule. Instead, it follows Markovnikov's rule, where the hydrogen atom adds to the more substituted carbon atom of the alkene. **Final Answer**: The addition of HCl does not obey anti-Markovnikov's rule because the high bond energy of HCl prevents the generation of free radicals necessary for this rule to apply. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

What is Markovnikov's rule ?

The addition of HCl in the presence of peroxide does not follow anti-Markownikoff's rule because

In the presence of peroxide, hydrogen chloride and hydrogen iodide do not give anti-Markovnikov's addition to alkenes because: