`CH_2=CH_2overset(Br_2//H_2O)to A`, In the above reaction the compound A is

Options

A. Ethylene bromohydrin
B. 1,2-dibromo ethane
C. Ethanol
D. None of these

Explanation

To solve the question regarding the reaction of ethylene (CH₂=CH₂) with Br₂ and H₂O to form compound A, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in the reaction are ethylene (CH₂=CH₂), bromine (Br₂), and water (H₂O).

### Step 2: Understand the Reaction Mechanism
In this reaction, bromine (Br₂) reacts with ethylene to form a bromonium ion intermediate. The bromonium ion is formed when one of the bromine atoms adds to one of the carbon atoms of the double bond, creating a three-membered ring structure.

### Step 3: Nucleophilic Attack
Water (H₂O) acts as a nucleophile and attacks the more substituted carbon of the bromonium ion. This results in the opening of the bromonium ion and leads to the formation of a bromohydrin.

### Step 4: Forming Compound A
The product formed from the above steps is 1-bromoethanol (or bromohydrin), which can be represented as:
- CH₂Br-CH₂OH

### Final Answer
The compound A formed in the reaction is 1-bromoethanol (or bromohydrin).

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