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CH-=CH underset(H2SO4)overset(HgSO4)to u...

`CH-=CH underset(H_2SO_4)overset(HgSO_4)to underset(H_2O)overset(CH_3MgBr)to overset(P//Br_2)to`

A

`CH_3CH(Br)CH_3`

B

`CH_3CH_2CH_2Br`

C

`CH_2=CH-Br`

D

`BrCH=CH-CH_3`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given reaction sequence step by step, let's break down each part of the process: ### Step 1: Hydration of Alkyne The reaction starts with an alkyne (specifically, CH≡CH). When treated with H₂SO₄ and HgSO₄, the alkyne undergoes hydration. This process adds water across the triple bond, resulting in the formation of a carbonyl compound (aldehyde or ketone). **Reaction:** \[ \text{CH≡CH} \xrightarrow{\text{H}_2\text{SO}_4, \text{HgSO}_4} \text{CH}_3\text{CHO} \] **Product:** Acetaldehyde (CH₃CHO) ### Step 2: Reaction with Grignard Reagent Next, the product (acetaldehyde) is treated with a Grignard reagent (CH₃MgBr). The Grignard reagent acts as a nucleophile and attacks the carbonyl carbon of the aldehyde. **Reaction:** \[ \text{CH}_3\text{CHO} + \text{CH}_3\text{MgBr} \rightarrow \text{CH}_3\text{C(OMgBr)H}_2 \] This intermediate will then be hydrolyzed in the presence of water. ### Step 3: Hydrolysis When the Grignard reagent intermediate is treated with water, it will form an alcohol. **Reaction:** \[ \text{CH}_3\text{C(OMgBr)H}_2 + \text{H}_2\text{O} \rightarrow \text{CH}_3\text{CH(OH)CH}_3 + \text{Mg(OH)Br} \] **Product:** 2-Propanol (CH₃CH(OH)CH₃) ### Step 4: Reaction with PBr₂ Finally, the alcohol (2-propanol) reacts with phosphorus tribromide (PBr₂). This step replaces the hydroxyl group (OH) with a bromine atom (Br). **Reaction:** \[ \text{CH}_3\text{CH(OH)CH}_3 + \text{PBr}_2 \rightarrow \text{CH}_3\text{CHBrCH}_3 + \text{HBr} + \text{PO} \] **Final Product:** 2-Bromopropane (CH₃CHBrCH₃) ### Summary of the Reaction Sequence: 1. CH≡CH + H₂SO₄ + HgSO₄ → CH₃CHO (Acetaldehyde) 2. CH₃CHO + CH₃MgBr → CH₃C(OMgBr)H₂ 3. CH₃C(OMgBr)H₂ + H₂O → CH₃CH(OH)CH₃ (2-Propanol) 4. CH₃CH(OH)CH₃ + PBr₂ → CH₃CHBrCH₃ (2-Bromopropane) Thus, the final product of the entire reaction sequence is **2-Bromopropane (CH₃CHBrCH₃)**.

To solve the given reaction sequence step by step, let's break down each part of the process: ### Step 1: Hydration of Alkyne The reaction starts with an alkyne (specifically, CH≡CH). When treated with H₂SO₄ and HgSO₄, the alkyne undergoes hydration. This process adds water across the triple bond, resulting in the formation of a carbonyl compound (aldehyde or ketone). **Reaction:** \[ \text{CH≡CH} \xrightarrow{\text{H}_2\text{SO}_4, \text{HgSO}_4} \text{CH}_3\text{CHO} \] ...
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