`CaC_2+H_2O to X overset(O_3//H_2O // OH^(+))to HCOOH` X is

Options

A. `C_2H_4`
B. `C_2H_2`
C. `C_2H_6`
D. `Ca(OH)_2`

Explanation

To solve the question, we need to analyze the reaction step by step.

### Step 1: Identify the initial reaction
The first step involves the reaction of calcium carbide (CaC₂) with water (H₂O). The equation for this reaction is:

\[ \text{CaC}_2 + \text{H}_2\text{O} \rightarrow \text{Ca(OH)}_2 + \text{C}_2\text{H}_2 \]

### Step 2: Determine the products
From the reaction, we can see that calcium carbide reacts with water to produce calcium hydroxide (Ca(OH)₂) and acetylene (C₂H₂).

### Step 3: Identify the next reaction
The next part of the question involves the ozonolysis of the product C₂H₂ in the presence of water and hydroxide ions (OH⁻):

\[ \text{C}_2\text{H}_2 \overset{\text{O}_3/\text{H}_2\text{O}/\text{OH}^-}{\rightarrow} \text{HCOOH} \]

### Step 4: Identify the final product
The ozonolysis of acetylene (C₂H₂) leads to the formation of formic acid (HCOOH).

### Conclusion
Thus, the intermediate product X formed from the reaction of calcium carbide with water is acetylene (C₂H₂).

### Final Answer
X is C₂H₂ (acetylene).

---