In reaction
`C_6H_5CH_3overset"oxidation"to A overset"NaOH"to B overset"sodalime"toC`
Then C is

Options

A. `C_6H_6`
B. `C_6H_5OH`
C. `C_6H_5COOoverset+Na`
D. `C_6H_5ONa`

Explanation

To solve the question step by step, let's analyze the reactions involved:

1. **Starting Compound**: The initial compound is toluene, which is represented as \( C_6H_5CH_3 \).

2. **Oxidation of Toluene**: When toluene undergoes oxidation, it is converted into benzoic acid (\( C_6H_5COOH \)). This is the first product, which we will denote as Product A.
- **Reaction**:
\[ C_6H_5CH_3 \xrightarrow{\text{oxidation}} C_6H_5COOH \]

3. **Reaction with NaOH**: The benzoic acid reacts with sodium hydroxide (NaOH) in an acid-base reaction to form sodium benzoate (\( C_6H_5COONa \)). This is the second product, which we will denote as Product B.
- **Reaction**:
\[ C_6H_5COOH + NaOH \rightarrow C_6H_5COONa + H_2O \]

4. **Decarboxylation with Soda Lime**: When sodium benzoate is treated with soda lime (a mixture of sodium hydroxide and calcium oxide), it undergoes decarboxylation. This means that the carboxyl group (\(-COOH\)) is removed, resulting in the formation of benzene (\( C_6H_6 \)). This is the final product, which we will denote as Product C.
- **Reaction**:
\[ C_6H_5COONa \xrightarrow{\text{soda lime}} C_6H_6 + Na2CO3 \]

5. **Final Result**: Therefore, the final product C is benzene (\( C_6H_6 \)).

### Summary of Products:
- Product A: Benzoic acid (\( C_6H_5COOH \))
- Product B: Sodium benzoate (\( C_6H_5COONa \))
- Product C: Benzene (\( C_6H_6 \))

### Final Answer:
C is benzene (\( C_6H_6 \)).

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