When `CH_2=CH-Br` is reacted with HBr then the product formed is A and when `CH_2=CH-COOH` is treated with HBr then the product formed is C. Hence here

Options

A. A is `undersetunderset(Br)|CH_2-undersetunderset(Br)|CH_2`
B.
C. C is `CH_3-undersetunderset(Br)|CH-COOH`
D. C is `undersetunderset(Br)|CH_2-CH_2-COOH`

Explanation

To solve the problem step by step, we will analyze the reactions of the compounds with HBr.

### Step 1: Reaction of CH2=CH-Br with HBr
1. **Identify the reactant**: The compound is CH2=CH-Br (vinyl bromide).
2. **Add HBr to the double bond**: When HBr is added to the alkene, the H+ ion will add to one of the carbons of the double bond, and the Br- ion will add to the other carbon.
3. **Determine the more stable carbocation**: The H+ will add to the carbon that will form a more stable carbocation. In this case, the carbon attached to Br will stabilize the positive charge better.
4. **Final product formation**: After the addition, we will have CH3-CHBr (bromoethane) as product A.

### Step 2: Reaction of CH2=CH-COOH with HBr
1. **Identify the reactant**: The compound is CH2=CH-COOH (acrylic acid).
2. **Add HBr to the double bond**: Similar to the first reaction, HBr will add across the double bond.
3. **Consider the electron-withdrawing effect of COOH**: The presence of the carboxylic acid group (COOH) is an electron-withdrawing group, which will influence the stability of the carbocation formed.
4. **Determine the more stable carbocation**: The H+ will add to the carbon that will lead to a more stable carbocation. In this case, it will add to the CH2 group, leading to a more stable carbocation on the carbon adjacent to COOH.
5. **Final product formation**: After the addition of HBr, we will have CH2Br-CH2-COOH as product C.

### Summary of Products
- Product A from the reaction of CH2=CH-Br with HBr is CH3-CHBr.
- Product C from the reaction of CH2=CH-COOH with HBr is CH2Br-CH2-COOH.