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Acetyl bromide reacts with excess of CH(...

Acetyl bromide reacts with excess of `CH_(3)MGI` followed by treatement with a saturated solution of `NH_(4)C1` gives:

A

2-methyl-2-propanol

B

Acetamide

C

Acetone

D

Acetyl iodide

Text Solution

Verified by Experts

The correct Answer is:
A
`underset("Acetyl bromide ")(CH_(3)-overset(O)overset(|)C-Br)underset((ii)"Saturated " NH_(4)Cl)overset((i) "Excess"-CH_(3)MgI)to underset(2-"methyl" 2-"propanol")(CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-OH)`
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