When a mixture of iodine , alcohol and aqueous sodium carbonate are heated, the product formed is

Options

A. Sodium formate and chloroform
B. Only `CO_(2)`
C. Iodoform and sodium formate
D. Ethyl carbonate and sodium iodide

Answer

To solve the question, we need to analyze the reaction between iodine, alcohol (specifically ethanol), and aqueous sodium carbonate when heated.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are iodine (I2), ethanol (C2H5OH), and sodium carbonate (Na2CO3).

2. **Understand the Reaction Conditions**:
- The mixture is heated. Heating can facilitate the reaction between these components, leading to the formation of new products.

3. **Reaction Mechanism**:
- When iodine reacts with ethanol in the presence of sodium carbonate, a reaction occurs where iodine is reduced and ethanol is oxidized. Sodium carbonate acts as a base in this reaction.

4. **Formation of Products**:
- The main products formed from this reaction are:
- Iodoform (CHI3), which is formed from the reaction of iodine with ethanol.
- Sodium formate (HCOONa), which is formed as a byproduct.

5. **Final Products**:
- Therefore, the products formed when a mixture of iodine, alcohol, and aqueous sodium carbonate is heated are iodoform (CHI3) and sodium formate (HCOONa).

### Conclusion:
The correct answer to the question is that the products formed are **iodoform and sodium formate**.

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