Which of the following on reaction with `Br_(2)` water will give 2,4,6-tribromo phenol

Options

A. Phenol
B. 4-hydroxy benzene sulphonic acid
C. Salicylic acid
D. None of these

Explanation

To determine which of the given compounds will yield 2,4,6-tribromo phenol upon reaction with Br2 in water, we will analyze each option step by step.

### Step 1: Understanding the Reaction
The reaction of phenolic compounds with bromine in water typically leads to bromination at the ortho and para positions due to the activating effect of the hydroxyl (-OH) group. This results in the formation of 2,4,6-tribromo phenol.

### Step 2: Analyze Each Compound
1. **Phenol (C6H5OH)**:
- When phenol reacts with Br2 in water, the -OH group activates the aromatic ring, allowing bromine to add at the ortho and para positions.
- The product will be 2,4,6-tribromo phenol.

2. **4-Hydroxybenzene sulfonic acid (C6H4(OH)(SO3H))**:
- The -OH group again activates the ring, and the sulfonic acid (-SO3H) group is a good leaving group.
- Upon bromination, the sulfonic acid group can leave, and bromine can add to the ortho and para positions, leading to the formation of 2,4,6-tribromo phenol.

3. **Salicylic acid (C7H6O3)**:
- Salicylic acid contains both -OH and -COOH groups. The -OH group activates the ring, and the -COOH group can also act as a leaving group.
- Bromination will occur at the ortho and para positions, resulting in 2,4,6-tribromo phenol.

4. **Other Compounds**:
- If there are additional options (not specified), we would need to analyze them similarly. However, based on the provided information, we can conclude that the first three compounds will yield 2,4,6-tribromo phenol.

### Conclusion
The compounds that will give 2,4,6-tribromo phenol upon reaction with Br2 in water are:
- Phenol
- 4-Hydroxybenzene sulfonic acid
- Salicylic acid

Thus, the answer is that options 1, 2, and 3 will yield 2,4,6-tribromo phenol.

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