Densities of diamond and graphite are `(3.5g)/(mL)` and `(2.3g)/(mL)`.
`Delta_(7)H=-1.9(kJ)/("mole")`
Favourable conditions for formation of diamond are:

Densities of diamond and graphite are (3.5g)/(mL) and (2.3g)/(mL) . Delta_(r)H=-1.9(kJ)/("mole") Favourable conditions for formation of diamond are:

Densities of diamond and graphite are 3.5g//mL and 2.3g//mL Delta_(r)H=-1.9kJ//mol Favourable conditions for formation of diamond are:

Densities of diamond and graphite are (3.5g)/(mL) and (2.3g)/(mL) . C (diamond) equilibrium C (graphite) Delta_(7)H=-1.9(kJ)/("mole") Favourable conditions for formation of diamond are:

Densities of diamond and graphite are 3.5 and 2.5 gm/ml. C_("daimond") hArr C_("graphite") , Delta_(t) H = -1.9 KJ/ mole favourable conditions for formation of diamond are

Densities of diamond and graphic are 3.5 and 2.5 gm/ml. C_("daimond") hArr C_("graphite") , Delta_(t) H = -1.9 KJ/ mole favourable conditions for formation of diamond are

Densities of diamond and graphite are 3.5 and 2.3 g mL^(-1) , respectively. The increase of pressure on the equilibrium C_("diamond") hArr C_("graphite")

Densities of diamond and graphite are 3.5 and 2.3 g mL^(-1) , respectively. The increase of pressure on the equilibrium C_("diamond") hArr C_("graphite")

The densities of graphite and diamond are 22.5 and 3.51 gm cm^(-3) . The Delta_(f)G^(ɵ) values are 0 J mol^(-1) and 2900 J mol^(-1) for graphite and diamond, respectively. Calculate the equilibrium pressure for the conversion of graphite into diamond at 298 K .

The densities of graphite and diamond are 22.5 and 3.51 gm cm^(-3) . The Delta_(f)G^(ɵ) values are 0 J mol^(-1) and 2900 J mol^(-1) for graphite and diamond, respectively. Calculate the equilibrium pressure for the conversion of graphite into diamond at 298 K .