The acceleration due to gravity at the equator becomes zero, if

The angular speed of earth's rotation about its own axis is omega . When its angular speed is increased to n time its original angular speed, the acceleration due to gravity at the equator becomes zero. What is the value of n? [R is the equatorial radius of the earth]

The angular speed of earth's rotation about its own axis is omega . When its angular speed is increased to n time its original angular speed, the acceleration due to gravity at the equator becomes zero. What is the value of n? [R is the equatorial radius of the earth]

Calculate that imaginary angular velocity of the Earth for which effective acceleration due to gravity at the equator becomes zero. In this condition, find the length (in hours) of a day? Radius of Earth = 6400 km. g = 10 ms^(-2) .

Calculate the angular velocity of the earth for which effective acceleration due to gravity at the equator becomes zero. In this condition, what will be the length of the day ? Take R_e =6400 km and g=10 m*s^(-2)

Acceleration due to gravity of earth

Define acceleration due to gravity.

What are acceleration due to gravity

Define acceleration due to gravity .

The acceleration due to gravity on the moon is