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The value of K(c) for the reaction : H(2...

The value of `K_(c)` for the reaction : `H_(2)(g)+I_(2)(g)hArr 2HI(g)` is 45.9 at 773 K. If one mole of `H_(2)`, two mole of `I_(2)` and three moles of HI are taken in a 1.0 L flask, the concentrations of HI at equilibrium at 773 K.

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The value of K_(c) for the reaction: H_(2)(g)+I_(2)(g) hArr 2HI (g) is 48 at 773 K. If one mole of H_(2) , one mole of I_(2) and three moles of HI are taken in a 1L falsk, find the concentrations of I_(2) and HI at equilibrium at 773 K.

The value of K_(c) for the reaction: H_(2)(g)+I_(2)(g) hArr 2HI (g) is 48 at 773 K. If one mole of H_(2) , one mole of I_(2) and three moles of HI are taken in a 1L falsk, find the concentrations of I_(2) and HI at equilibrium at 773 K.

The value of K_(c) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) is 64 at 773K . If one "mole" of H_(2) , one mole of I_(2) , and three moles of HI are taken in a 1 L flask, find the concentrations of I_(2) and HI at equilibrium at 773 K .

The value of K_(c) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) is 64 at 773K . If one "mole" of H_(2) , one mole of I_(2) , and three moles of HI are taken in a 1 L flask, find the concentrations of I_(2) and HI at equilibrium at 773 K .

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The equilibrium constant K_(p) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) changes if:

One mole of H_2 , 2 moles of I_2 and 3 moles of HI are injected in a one litre of flask. What will be the concentration of H_2, I_2 and HI at equilibrium when K_c is 45.9 ?

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For the reaction 2HI(g)hArr H_(2)(g)+I_(2)(g) . The value of K_(c) is 4. If 2 moles of H_(2)," 2 moles of "I_(2) and 2 moles of HI are present in one litre container then moles of I_(2) present at equilibrium is :