No. of uranium `235` nuclei required to undergo fission to give `9xx10^(13)` joule of energy is

In a nuclear reactor, the number of U^(235) nuclei undergoing fissions per second is 4xx10^(20). If the energy releases per fission is 250 MeV, then the total energy released in 10 h is (1 eV= 1.6xx10^(-19)J)

In a nuclear reactor, the number of U^(235) nuclei undergoing fissions per second is 4xx10^(20). If the energy releases per fission is 250 MeV, then the total energy released in 10 h is (1 eV= 1.6xx10^(-19)J)

How much mass of " ^235U is required to undergo fission each day to provide 3000 MW of thermal power? Average energy per fission is 202.79 Mev?

Which isotope of uranium can undergo fission readily?

If 200 MeV of energy is released in the fission of one nucleus of ""^(236)_(92)U , the number of nuclei that must undergo fission to release an energy of 1000 J is,

If 200 MeV of energy is released in the fission of one nucleus of ._92U^235 , The number of nuclei that must undergo fission to produce energy of 1000J in 1 sec is

If 200 MeV of energy is released in the fission of 1 nucleus of ._(92)U^(235) , the number of nuclei that undergo fission to produce energy of 10 kWh in 1 s is

In fission of one uranium-235 nucleus, the loss in mass is 0.2 a.m.u. Calculate the energy released.

In a nuclear reactor .^235U undergoes fission liberating 200 MeV of energy. The reactor has a 10% efficiency and produces 1000 MW power. If the reactor is to function for 10 yr , find the total mass of uranium required.