Velocity and acceleration of a particle are `v=(2 hati-4 hatj) m/s` and `a=(-2 hati+4 hatj) m/s^2` Which type of motion is this?

Velocity and acceleration of a particle are v=(2 hati) m/s and a = (4t hati+t^2 hatj) m /s^2 where, t is the time. Which type of motion is this ?

Velocity and acceleration of a particle are v=(2 hati) m/s and a = (4t hati+t^2 hatj) m /s^2 where, t is the time. Which type of motion is this ?

Velocity and acceleration of a particle at time t=0 are u=(2 hati+3 hatj) m//s and a=(4 hati+3 hatj) m//s^2 respectively. Find the velocity and displacement if particle at t=2s.

Velocity and acceleration of a particle at time t=0 are u=(2 hati+3 hatj) m//s and a=(4 hati+3 hatj) m//s^2 respectively. Find the velocity and displacement if particle at t=2s.

Assertion : Velocity and acceleration of a particle are given as, v=hati-hatj and a=-2 hati+2 hatj This is a two dimensional motion with constant acceleration. Reason : Velocity and acceleration are two constant vectors.

Assertion : Velocity and acceleration of a particle are given as, v=hati-hatj and a=-2 hati+2 hatj This is a two dimensional motion with constant acceleration. Reason : Velocity and acceleration are two constant vectors.

Velocity and acceleration of a particle at time t=0 are vecu =(2hati + 3hatj)m//s s and a = (4hati +2hatj) m//s^(2) respectively. Find the velocity and displacement of particle at t = 2s.

Velocity and accleration of a [article at time t=0 are vecu=(2hati+3hatj) m/s and veca=(4hati+2hatj)m//s^(2) respectively. Find the velocity and dispalcement of the particle at t-2s.

The initial velocity and the acceleration of a particle are vecu=3hati+4hatj and veca=0.3 hati+0.4hatj . The magnitude of its velocity after 10 s is