A body of mass 1 kg starts moving from rest `t = 0` in a circular path of radius 8 m. Its kinetic energy varies with time as `k = 2t^(2) J` then magnitude of centripetal acceleration ( in `m//s^(2)` ) at `t = 2s` is.

A body of mass 1 kg starts moving from rest t = 0 in a circular path of radius 8 m. Its kinetic energy varies with time as k = 2t^(2) J then the correct statement are:

A body starts revolving from rest in a circular path of radius 2 m with tangential acceleration a =2tm//s^(2) . If its total acceleration at t=2 sec. is nsqrt(5) m//s^(2) , then the value of n is:

A body performs S.H.M. Its kinetic energy K varies with time t as indicated by graph

A body performs S.H.M. Its kinetic energy K varies with time t as indicated by graph

A body of mass 10 kg moves with a velocity of 2 m/s along a circular path of radius 8 m. The power produced by the body will be

A body of mass m is moving along a circular path of radius R such that its kinetic energy at any instant is k=k_(0)((t)/(t_(0)))^(2) where t_(0) is an appropriate constant. Then

A particle is performing circular motion of radius 1 m. Its speed is v=(2t^(2)) m//s . What will be magnitude of its acceleration at t=1s .

A particle is performing circular motion of radius 1 m. Its speed is v=(2t^(2)) m//s . What will be magnitude of its acceleration at t=1s .

A particle is performing circular motion of radius 1 m. Its speed is v=(2t^(2)) m//s . What will be magnitude of its acceleration at t=1s .

A particle lis constrained to move in a circular path of radius r = 6m. Its velocity varies with time according to the relation v = 2t (m/s). Determine its (i) centripetal acceleration, (ii) tangential acceleration, (iii) instantaneous acceleration at (a) t = 0 sec. and (b) t = 3 sec.