What should be the weight suspended from the end of a steel wire 2 m in length and w mm in diameter to increase the length by 1 mm ?
`(Y=19xx10^(11)N//m^(2))`

What mass must suspended from the free end of a steel wire of length 2m and diameter 1mm to stretch it by 1mm ? (Y=2xx10^(11)Nm^(-2))

What mass must by suspended from free end of steel wire of length 2m and diameter 1 mm to stretch it by 1 mm ? (Y = 2 xx 10^11 N/m^2,g = 9.8m/s^2)

How much load should be hung from the end of a steel wire of length 3.14 m and of diameter 1 mm so that it increases in length by 1mm? Y for steel is 2 times 10^11 SI unit.

An aluminum wire and a steel wire of the same length and cross-section are joined end to end. The compoiste wire is hung from a rigid support and a load is suspended from the free end. If the length of the composite wire is 2.7mm then the increases in the length of wire is (in mm ) (Y_(Al) = 2xx10^(11)Nm^(2), Y_("Steel") = 7xx10^(11) Nm^(-2))

An aluminium wire and a steel wire both of the same length and cross-section are joined end to end . The composite wire is hung from a rigid support and a load is suspended from the free end . If the increase in length of the composite wire is 2.7 mm, find the increase in length of each wire. Y_al = 7 xx 10^10 N/m^2 and Y_steel = 2 xx 10^11 N/m^2 .

An aluminium wire and a steel wire are of the same length and crosssection and are joined end to end. The composite wire is hung from a rigid support, a load is suspended from the free end. If the increase in the length of composite wire is 2.77 mm, find the increase in length of each wire. ( Y_A = 7 xx 10^10 N/m^2) (Y steel= 2 xx 10^11 N//m^2)

An aluminium wire and a steel wire of the same length and cross-section are joined end to end. The composite wire is hund from a rigid support and a load is suspended from the free end. If the increase in the length of the composite wire is 2.7mm, find the increase in the length of each wire. (Y_(Al)=0.7xx10^(11)Nm^(-2), Y_("steel")=2xx10^(11)Nm^(-2))

A 5 kg wt is suspended from the end of a wire 2.5 m long fixed to a rigid support. The diameter of the wire is 2 mm. If Y = 20 x 10^10 N/m^2 for the material of the wire, find the increase in its length.g = 9.8 m/s^2 .

Longitudinal stress of 1 kg//mm^(2) is applied on a wire. The percentage increase in length is (Y = 10^(11) N//m^(2))