The potential difference between the terminals of a cells is found to be 3 volts when it is connected to a resistance equal to its internal resistance. The e.m.f. of the cell is :–

The poten tial difference between the terminals of a cells is found to be 3 volts when it is connected to a resistance equal to its internal resistance. The e.m.f. of the cell is:-

The poten tial difference between the terminals of a cells is found to be 3 volts when it is connected to a resistance equal to its internal resistance. The e.m.f. of the cell is:-

The potential difference between the terminals of a cell, in an open circuit was 2.5 volt and when it was connected through a resistance of 5 ohm, the potential difference fell to 1.5v. Find the internal resistance of the cell.

For the determination of emf E and internal resistance 'r' of a cell , the graph is obtained between potential difference V between the terminal of the cell against the current l, which was changed by adjusting the rheostat, is as shown . The internal resistance of the cell is

For a Cell, the terminal potential difference is 2.2 V when circuit is open and reduces to 1.8 V, when cell is connected to a resistance R = 5Omega . The internal resistance of cell (r ) is

For a cell, the terminal potential difference is 2.2 V , when circuit is open and reduces to 1.8 V . When cell is connected to a resistance R=5Omega , the internal resistance of cell (R) is

For a cell terminal potential difference is 2.2 V when circuit is open and reduces to 1.8V when cell is connected to a resistance of R= 5Omega then determine internal resistance of cell is:-

For a cell, the terminal potential difference is 2.2 V , when circuit is open and reduces to 1.8 V . When cell is connected to a resistance R=5Omega , the internal resistance of cell (R) is

For a cell, the terminal potential difference is 2.2 V , when circuit is open and reduces to 1.8 V . When cell is connected to a resistance R=5Omega , the internal resistance of cell (R) is

For a cell terminal potential difference is 2.2 V when circuit is open and reduces to 1.8V when cell is connected to a resistance of R= 5Omega then determine internal resistance of cell is:-