Electronic transition in `He^(+)` ion takes from `n_(2) " to " n_(1)` shell such that :
`2n_(2)+3n_(1)=18`
`2n_(2)+3n_(1)=6`
What will be the total number of photons emitted when electrons transit to `n_(1)` shell?

The transition of an electron from n_(2)=5,6 ….. To n_(1) =4 gives rise to

Calculate the wavelength of a photon emitted when an electron in H- atom maker a transition from n=2 to n=1

Calculate the wavelength of a photon emitted when an electron in H- atom maker a transition from n=2 to n=1

The electronic transition from n=2 to n=1 will produce shortest wavelength in:

The atomic structure of He^(+) arises due to transition from n_(2) to n_(1) level. If n_(1)+n_(2) is 3 and n_(2)-n_(1) is 1. Find the lambda in nm of transition for this series in He^(+) in nm.

The atomic structure of He^(+) arises due to transition from n_(2) to n_(1) level. If n_(1)+n_(2) is 3 and n_(2)-n_(1) is 1. Find the lambda in nm of transition for this series in He^(+) in nm.

An electron makes transition form n=3 , n=1 state in a hydrogen atom. The maximum possible number of photons emitted will be

The atomic spectrum of Li^(2+) arises due to the transition of an electron from n_(2) to n_(1) level. If n_(1) +n_(2) is 4 and n_(2)-n_(1) is 2, calculate the wavelength (in nm) of the transition for this series in Li^(2+)