A satellite is projected with a velocity `sqrt(1.5)` times the orbital velocity just above the surface of earth. Initial velocity of the satellite is perpendicular to the surface of earth. The maximum distance of the satellite from surface of earth will be -

A satellite is put in an orbit just above the earth's atmosphere with a velocity sqrt(1.5) times the velocity for a circular orbit at the that height. The initial velocity imparted is horizontal. What would be the maximum distance of the satellite from the earth, when it is in the orbit.

The orbit velocity of a satellite at a height R above the surface of Earth is v . The escape velocity from the location is

The orbital velocity of a satellite very near to the surface of earth is v. What will be its orbital velocity at an altitude 7 times the radius of the earth?

An artificial satellite is moving in circular orbit around the earth with speed equal to half the magnitude of escape velocity from the surface of earth. R is the radius of earth and g is acceleration due to gravity at the surface of earth (R = 6400km) Then the distance of satelite from the surface of earth is .

If v_(0) be the orbital velocity of an articial satellite orbital velocity of the same satellite orbiting at an altitude equal to earth's radius is

Suppose the orbit of a satellite is exatly 35780 km above the earth's surface. Determine the tangential velocity of the satellite.

A satellite is orbiting with areal velocity v_(a) . At what height form the surface of the earth, it is rotating, if the radius of earth is R ?