Electric flux through a surface of area `100 m^(2)` lying in the plane in the xy plane is (in V-m) if `E=hat(i)sqrt(2)hat(j)+sqrt(3)hat(k)`:

Electric flux through a surface of area 100m^2 lying in the xy plane is (in V-m) if vec E= hat i+ sqrt 2hat j + sqrt 3 hat k- .

Find out the electric flux through an area 10 m^(2) lying in XY plane due to a electric field vec(E)=2hat(i)-10 hat(j)+5hat(k) .

If side vec AB of an equilateral trangle ABC lying in the x-y plane 3hat i ,then side vec CB can be -(3)/(2)(hat i-sqrt(3)hat j) b.-(3)/(2)(hat i-sqrt(3)hat j) c.-(3)/(2)(hat i+sqrt(3)hat j) d.(3)/(2)(hat i+sqrt(3)hat j)

An electric field is given by (6 hat i 5 hat j 3 hat k) N/C. The electric flux through a surface area 30 hat i m^2 lying in YZ-plane (in SI unit) is :

The plane through the point (-1,-1,-1) and containing the of intersection of the planes r*(hat(i)+3hat(j)-hat(k))=0andr*(hat(j)+2hat(k))=0 is

Find all vectors of magnitude 10sqrt(3) that are perpendicular to the plane of hat(i)+2hat(j)+hat(k) and -hat(i)+hat(j)+4hat(k) .

If the electric field is given by vec(E) = 8 hat(i) + 4 hat(j) + 3 hat(k) NC^(-1) , calculate the electric flux through a surface of area 100 m^(2) lying in X-Y plane.

If the electric field given by (5hat(i)+4hat(j)+9hat(k)) , then the electric flux through a surface of area 20 unit lying in the yz - plane will be

Position vector hat k is rotated about the origin by angle 135^0 in such a way that the plane made by it bisects the angle between hat ia n d hatjdot Then its new position is a.+-( hat i)/(sqrt(2))+-( hat j)/(sqrt(2)) b. +-( hat i)/2+-( hat j)/2-( hat k)/(sqrt(2)) c. ( hat i)/(sqrt(2))-( hat k)/(sqrt(2)) d. none of these