Consider `psi` (wave function) of `2s` atomic orbital of H-atom is-
`psi_(2s)=(1)/(4sqrt(2pia_(0)^(3//2)))[2-(r )/(a_(0))]e^.(r )/(2a_(0)`
Find distance of radial node from nucleous in terms of `a_(0)`

The Wave function (Psi) of 2s is given by: Psi_(2s)=(1)/(2sqrt2pi)(1/a_(0))^(1//2){2-(r)/a^(0)}e^(-r//2a_(0)) At r =r_(0) , radial node is formed . Thus for 2s ,r_(0), in terms of a_(0) is-

The Schrodinger wave equation for the 2s electron of a hydrogen atom is, psi_(2s)=(1)/(4sqrt(2pi))[(1)/(a_(0))]^(3//2)xx[2-(r)/(a_(0))]xxe^(-r//2a_(0)) There is a radial node at the point, where r=r_(0) find the relation between r_(0) and a_(0) .

psi_(1s)=(1)/(sqrt(pia_(0)^(3//2)))e^((r )/(a_(0))) Find the distance r from nucleous at which e^(-) finding probability is max. [For H-atom] a_(0)rarrI Bohr radius

a.The schrodinger wave equation for hydrogen atom is psi_(2s) = (1)/(4sqrt(2pi)) ((1)/(a_(0)))^((3)/(2)) (2 - (r_(0))/(a_(0)))e^((-(r )/(a)) When a_(0) is Bohr's radius Let the radial node in 2s be n at Then find r_(0) in terms of a_(0) b. A base ball having mass 100 g moves with velocity 100 m s^(-1) .Find the value of teh wavelength of teh base ball

The wave function of atomic orbital of H-like atom is R_(2,0) or R_(2s)=(1)/(4sqrt(2pi)) Z^(3//2) (2-Zr) e^(Zr//2) Given that the radius is in Å, then what is the radius for nodal surface for He^(+) ion.