A rod is of length `3` m and its mass acting per unit length is directly proportional to distance x from its one end. The centre of gravity of the rod from that end will be at

A rod of length 3m and its mass par unit length is directly proportional to the distance x from its one end . The centre of gravity of the rod from that end will be at :-

A rod of length 3 m has its mass per unit length directly proportional to distance x from one of its ends then its centre of gravity from that end will be at

A rod of length L is of non uniform cross-section. Its mass per unit length varies linearly with distance from left end. Then its centre of mass from left end is at a distance. (Take linear density at left end=0).

A rod of length L is of non uniform cross-section. Its mass per unit length varies linearly with distance from left end. Then its centre of mass from left end is at a distance. (Take linear density at left end=0).

If the linear density (mass per unit length) of a rod of length 3 m is proportional to x , where x , where x is the distance from one end of the rod, the distance of the centre of gravity of the rod from this end is.

The mass per unit length of a non-uniform rod of length L is given by mu= lamdaxx2 ​, where lamda is a constant and x is distance from one end of the rod. The distance of the center of mass of rod from this end is :-

The mass per unit length of a non-uniform rod of length L is given by mu = lambdax^2 , where lambda is constant and x is distance from one end of the rod. The distance of the center of mass of rod from this end is