The refractive index `mu` of a medium is found to vary with wavelength `lambda` as `mu = A +(B)/(lambda^2).` What are the dimensions of A and B?

Refractive index (mu) of a medium depends upon

When light of wavelength lambda travels through glass, the refractive index of glass varies with wavelength as mu=A+(B)/(lambda^(2)) . What are the dimensional formulae of A and B?

The refractive index ( mu ) of glass is related to the wavelength (lambda) of incident light as mu = A +(B)/(lambda^(2)) , where A and B are constants. Find out the dimensions of A and B.

The relation between refractive index and the wavelength light mu= A + B//lambda^2 . What is the dimension of B?

How does refractive index (mu) of a material vary with respect to wavelenght (lambda) . (A and B are constants).

When white light travels through glass, the refractive index of glass ( mu =velocity of light in air/velocity of light in glass) is found to vary with wavelength as mu=A+(B)/(lambda^(2)) . Using the principle of homogeneity of dimensions, Find the SI units in which the constants A and B expressed.

When white light travels through glass the refractive index mu=(velocity of light in air/velocity of light in glass) is found to very with waveless as mu=A+B/lambda^2 where A and B are constants. Using the principle of homogeneity of dimensions, determine the SI unit in which A and B must be expressed.

The refractive index of light in glass varies with its wavelength according to equation mu (lambda) = a+ (b)/(lambda^(2)) where a and b are positive constants. A nearly monochromatic parallel beam of light is incident on a thin convex lens as shown. The wavelength of incident light is lambda_(0) +-Delta lambda where Delta lambda lt lt lambda_(0) . The light gets focused on the principal axis of the lens over a region AB. If the focal length of the lens for a light of wavelength lambda_(0) is f_(0) , find the spread AB.

The refractive index of a medium is given by mu=A+(B)/(lambda^(2)) where A and B are constants and lambda is the wavelength of light. Then the dimensions of B are the same as that of

The correct curve between refractive index mu and wavelength lambda will be