The compressibility factor (Z) of a gas at critical state is
`(T_(e)=(8a)/(27Rb),p_(e)=(a)/(27b^(2)),V_(e)=3b)`

The compressibility factor Z = ((PV)/(nRT)) of a gas above T = (a)/(Rb) will be :

The compressibility factor Z = ((PV)/(nRT)) of a gas above T = (a)/(Rb) will be :

The value of compressibility factor at the critical state the gas matches with the Z_(c ) is

27 x^(2) e^(3x)

Compressibility factor Z=(PV)/(RT) . Considering ideal gas, real gas, and gases at critical state, answer the following questions: Z_(c) at T_(c) , P_(c) , and V_(c) is

Compressibility factor Z=(PV)/(RT) . Considering ideal gas, real gas, and gases at critical state, answer the following questions: Z_(c) at T_(c) , P_(c) , and V_(c) is

The essential conditions for liquefaction of gases were discovered by Andrews in 1869 as a result of his study of pressure-volume-temperature relationship for CO_(2) . If was found that above a certain temperature, it was impossible to liquefy a gas whatever the pressure was applied. The temperature below which the gas can be liquefied by the application of pressure alone is called critical temperature (T_(c)) . The pressure required to liquefy a gas at this temperature is called the critical pressure (P_(c)) . The volume occupied by one mole of the substance at the critical temperature and pressure is called critcal volume. Critical constants are related with van der Waals' constant as follows: V_(c) = 3b, P_(c) = (a)/(27b^(2)), T_(c) = (8a)/(27 Rb) {:("Gases",A,B,C,D,),(P_(c) (atm),2.2,14,35,45,),(T_(c) (K),5.1,33,127,140,):} Which of the above gases cannot be liquefied at 100 K and 50 atm ?

The essential conditions for liquefaction of gases were discovered by Andrews in 1869 as a result of his study of pressure-volume-temperature relationship for CO_(2) . If was found that above a certain temperature, it was impossible to liquefy a gas whatever the pressure was applied. The temperature below which the gas can be liquefied by the application of pressure alone is called critical temperature (T_(c)) . The pressure required to liquefy a gas at this temperature is called the critical pressure (P_(c)) . The volume occupied by one mole of the substance at the critical temperature and pressure is called critcal volume. Critical constants are related with van der Waals' constant as follows: V_(c) = 3b, P_(c) = (a)/(27b^(2)), T_(c) = (8a)/(27 Rb) Gas A and can be liquefied at room temperature by applying pressure but gas B cannot. This reflects: