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In Question 2 above, if 1 part of a red ...

In Question 2 above, if 1 part of a red pigment requires 75 mL of base, how much red pigment should we mix with 1800 mL of base?

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Here the solution is:
Let the number of parts of red pigment be `x` and the parts of base be `y`.
As no.of parts of red pigment increases, the amount of base also increases in the same ratio. So they are in direct proportion.
Two numbers `x` and `y` are said in direct proportion if, the relationship between two quantities is such that if we increase one, the other will also increase, and if we decrease one the other quantity will also decrease.
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