As shown, a big box of mass M is resting on a horziontal smooth florr. On the bottom of the box there is a small block of mass m. The block is given an intial speed `v_(0)` relative to the floor, and starts to bounce back and forth between the two walls of the box. Find the final speed of the box when the block has finally come to rest in the box :-

The block shown in figure is released from rest. Find out the speed of the block when the spring is compressed by 1 m

A block is mass m moves on as horizontal circle against the wall of a cylindrical room of radius R. The floor of the room on which the block moves is smooth but the friction coefficient between the wall and the block is mu . The block is given an initial speed v_0 . As a function of the speed v write a. the normal force by the wall on the block. b. the frictional force by the wall and c. the tangential acceleration of the block. d. Integrate the tangential acceleration ((dv)/(dt)=v(dv)/(ds)) to obtain the speed of the block after one revoluton.

A block is mass m moves on as horizontal circle against the wall of a cylindrical room of radius R. The floor of the room on which the block moves is smooth but the friction coefficient between the wall and the block is mu . The block is given an initial speed v_0 . As a function of the speed v write a. the normal force by the wall on the block. b. the frictional force by the wall and c. the tangential acceleration of the block. d. Integrate the tangential acceleration ((dv)/(dt)=v(dv)/(ds)) to obtain the speed of the block after one revoluton.

A block of mass m moving at a speed v collides with another block of mass 2 m at rest.The lighter block comes to rest after the collision.Find the coefficient of restitution.

What should be the acceleration a of the box shown in figure so that the block of mass m exerts a force (mg)/(4) on the force of the box?

What should be the acceleration a of the box shown in figure so that the block of mass m exerts a force (mg)/(4) on the force of the box?

A block of mass m moving with speed v collides with another block of mass 2m at rest. The lighter block comes to rest after the collision. The coefficient of restitution is