`int(cos2x)/(sinx+cosx)dx=`

Evaluate: int(cos2x)/(sinx+cosx)^2dx

Find int(cos2x)/((sinx +cosx)^(5))dx

Choose the correct answers int(cos2x)/((sinx+cosx)^2)dx is equal (A) (-1)/(sinx+cosx)+C (B) log|sinx+cosx|+C C) log|sinx-cosx|+C (D) 1/((sinx+cosx)^2)

Choose the correct answers int(cos2x)/((sinx+cosx)^2)dx is equal(A) (-1)/(sinx+cosx)+C (B) log|sinx+cosx|+C C) log|sinx-cosx|+C (D) 1/((sinx+cosx)^2)

int(cos2x)/(cosx-sinx)dx=

The value of int(cos2x)/(sinx+cosx)^(2) dx is equal to