Let `A=[{:(1,-2,-3),(0,1,0),(-4,1,0):}]` Find adj A.

A=[{:(1,-1,2),(2,3,5),(-2,0,1):}] then find (adj A)

If A =[{:(1,-1,1),(0,2,-3),(2,1,0):}] and B = (adj A) , and C = 5A , then (|adjB|)/( |C |) is equal to :

If A = [(-4,-3,-3),(1,0,1),(4,4,3)] , find adj (A)

A=[(1,-3,1),(2,0,4),(1,2,-2)] Find |adj A|

If A =[{:(2,0,0),(0,1,0),(0,0,1):}] then adj(A) =

Let A be a 3 xx 3 matrix such that adj A = [{:(,2,-1,1),(,-1,0,2),(,1,-2,-1):}] and B =adj (adj A) . If |A| = lambda and |(B^(-1))^T| = mu then the ordered pair (|lambda|, mu) is equal to

Find adj (adj(A)) if adj A = [{:(1,0,1),(0,2,0),(-1,0,1):}] .

Verify : A(adj.A)=(adj.A)A=|A|I when : A=[{:(1,2,3),(0,5,0),(2,4,3):}]

Let A=[(-1,2,4),(1,1,3),(3,2,3)] Find Adj A.