If `I=50kg m^(2)`, then how much torque will be applied to stop it in 10 sec. Its initial angular speed is 20 rad/sec?

A particle starts moving at t = 0 in a circle of radius R = 2m with constant angular acceleration of a - 3 "rad/sec"^(2) . Initial angular speed of the particle is 1 rad/sec. At time t_(0) the angle between the acceleration vector and the velocity vector of the particle is 37^(@) . What is the value of t_(0) ?

A wheel is rotating about a its own axis. The moment of inertia of the wheel about axis of rotation.If its angular speed is 30 rad/sec and its kinetic energy is 300J ( in kg-m^(2))

A vehicle of 100 kg is moving with velocity of 5 m/s. How much force will be required to stop in 1/10 sec ?

A sphere of moment of inertia 10kgm^(2) is rotating at a speed of 100 rad/s. Calculate the torque required to stop it in 10 minutes. Also calculate the angular momentum of the wheel two minutes before it stops rotating.

A torque of 50 N-m acting on a wheel at rest rotates it through 200 rad in 5 sec. Its angular acceleration is -

A constant torque of 200 Nm turns a wheel of moment of inertia 50 kg m^(2) about an axis through its centre. The angualr velocity 2 sec after staring form rest (in rad/sec) would be :

Raju increased the speed of moving mass '50kg' from 2m/s to 4m/s. How much force will be required, if velocity change takes place with in 0.2 sec?

A current carrying ring, carrying a constant current (2)/(pi) Amp , radius 1m mass (2)/(3)kg having 10 windings is free to rotate about its tangential vertical axis. A uniform magnetic field of 1 tesla is applied perpendicular to its plane. How much minimum angular velocity (in rad/sec) should be given to the ring in the direction shown, so that it can rotate 270^(@) in that direction. Write your answer in nearest single digit in rad/sec