If cone of height `h` and base radius `r` has volume `V_1` is melted and reshape to form cube of side `a` and volume `V_2` then

A cylindrica bar of metal has a base radius of 2 and a height of 9. It is melted down and reformed into a cube. A side of the cube is

Two solid right cones of equal height and radii r_(1) and r_(2) are melted and made to form a solid sphere of radius R. Then the height of the cone is

Two solid right cones of equal heights are of radii r_1 and r_2 are melted and made to form a solid sphere of radius R. Then the height of the cone is:

If the height and the radius of a cone are doubled, the volume of the cone becomes

If the height of a given cone becomes four times and the radius of the base becomes twice, what is ratio of the volume of the given cone and the volume of the new cone ?

If the radius of the base of a cone is tripled and the height is doubled then the volume is

A cone of height h is inscribed in a sphere of radius R , if the volume of the inscribed cone is maximum, then the value of h : R will be-

A cylinder and a cone are of same base radius and of same height. Find the ratio of the volume of the cylinder to the volume of the cone.