The function `f(x) = (log(1+ax)-log(1-bx))/(x)` is not defined at x = 0. The value which should be assigned to f at x = 0 so that it is continuous at x = 0, is

The function f(x) = (log(1+ax)-log(1-bx))/x is not difined at x = 0. The value which should be assigned to f at x = 0, so that it is continuous at x = 0, is

The function f(x) = ([log (1 + ax) - log (1-bx)])/(x) is not defined at x = 0. The value, which should be assrgned to f at x = 0. The value, which should be assrgned to f at x = 0 so that it is continuous at x = 0 is :

The function f(x) = (log(1+ax)-log(1-bx))/x is not defined at x = 0. Find the value of f(0) so that f is continuous at x = 0

If the function f(x)=(log(1+ax)-log(1-bx))/(x) is continuous at x=0, then f(0)=

f(x)=(1)/(x)["log"(1+bx)-"log"(1-ax)] is not defined at x=0 . What value is to be assigned to f (0) so that f (x) will be continuous at x=0?

The funtion f(x)=(log(1+ax)-log(1-bx))/x is not define at x=0. Find the value of f(0),so that f(x)is continuous at x=0.

f(x)={(log(1+2ax)-log(1-bx))/(x),x!=0x=0

f(x) = ( log (1 +ax ) - log (1 - bx))/(x) is continuous at x = 0 then f(0) =