The curve satisfying `ydx-xdy+lnx dx=0, ( x gt 0)` passing through `(1,-1)` is

Find the equation to the curve satisfying x(x+1)(dy)/(dx)-y=x(x+1) and passing through (1,0)

If the curve satisfying (xy^(4) + y)dx - xdy = 0 passes through (1,1) then the value -41(y(2))^(3) is _______

If the curve satisfying (xy^(4) + y)dx - xdy = 0 passes through (1,1) then the value -41(y(2))^(3) is _______

Find the equation to the curve satisfying x(x+1)(dy)/(dx)-y=x(x+1) and passing through (1,0)dot

The curve satisfying (d^(2)y)/(dx^(2))-4y'=0 and passing through (1,0) is

The curve satisfying (d^(2)y)/(dx^(2))-4y'=0 and passing through (1,0) is

Solve: ydx-xdy+dx=0

If the curve satisfying ydx+(x+x^(2)y)dy=0 passes through (1,1) then ((-4log_(3)(4)+(1)/(y(4)))/(2)) is equal to