Electric field at a distance x from the origin is given as `E =(100N-m^2//C)/x^2` . Then potential difference between the points situated at x = 10 m and x = 20m is :-

If the electric field is given by vec(E ) = ((100)/(x^(2)))i the potential difference between points x=10m and x=20m in volts is

Figure shows the variation of electric field intensity E with distance x. The potential difference between the point x = 0 and x= 5m is

Magnitude of electric field only on the x-coordinate as vec(E)=20/x^(2) hat(i) V//m . Find (i) The potential difference between two points A (5m, 0) and B (10m, 0). (ii) Potential at x = 5 if V at oo is 10 volt.

Magnitude of electric field only on the x-coordinate as vec(E)=20/x^(2) hat(i) V//m . Find (i) The potential difference between two points A (5m, 0) and B (10m, 0). (ii) Potential at x = 5 if V at oo is 10 volt. (iii) In part (i), does the potential difference between a and B depend on whether the potential at oo is 10 volt or something else.

Figure shows the variation of electric field intensity E versus distance x. The magnitude potential difference between the point at x = 0 to x = 6 m will be

Two point A and B are situated at distance 1 m and 2m form the source of an electrostatic field. The field at a distance x from the source is E = (5)/(x^2) . What is the potential difference between A and B?

An electric field of 20N/C exists along the X-axis in space. Calculate the potential difference VB - VA where the points A and B are given by, A = (4m, 2m), B = (6m, 5m)