In Fraunhofer diffraction pattern, slit width is `0.2 mm` and screen is at 2 m away from the lens. If wavelength of light used is `5000 Å`, then the distance between the first minimum on either side of the central maximum is (`theta` is small and measured in radian)

In a double experiment, the distance between the slit is 1 mm and screen is 25 cm away from the slits. The wavelength of light is 6000Å . The width of the fringe on the screen is

In Fraunhofer diffraction by a narrow slit, a screen is placed at a distance of 2m from the lens to obtain the diffration pattern. If the Slit width is 0.2mm and the first minimum is 5mm on either side of central maximum, find the wavelength of light.

Through a narrow slit of width 2 mm, diffraction pattern is formed on a screen kept at a distance 2 m from the slit. The wavelength of the light used is 6330 A and falls normal to the slit and screen. Then, the distance between the two minima on either side of the central maximum is

In Fraunhaffer diffraction by a narrow slit, a screen is placed, at a distance of 2 m, from the lens to obtain a diffraction pattern. If the slit width is 0.2 mm and the first minimum is 5 mm, on either side of the central maximum. Find the wavelength of light.

A screen is placed 2m away from the single narrow slit. Calculate the slit width if the first minimum lies 5 mm on either side of the central maximum. Incident plane waves have a wavelength of 5000 Å .

For producing a fraunhofer diffraction fringe, a screen is placed 2m away from a single narrow slit. If the width of slit is 0.2 mm, it is found that first minimum lies 5 mm on either side of the central maximum. Find the wavelength of the incident light.

The distance between the first and the sixth minima in the diffraction pattern of a single slit is 0.5 mm. The screen is 0.5 m away from the slit. If the wavelength of light used is 5000 Å. Then the slit width will be