171 g of cane sugar `(C_(12) H_(22) O_(11))` is dissolved in 1 litre of water. The molarity of the solution is

The molal freezing point constant of water is 1.86 ^(@) C m^(-1) . If 342 g of cane sugar (C_(12)H_(22)O_(11)) is dissolved in 1000 g of water, the solution will freeze at

The molal freezing point constant of water is 1.86 K m^(-1) . If 342 g of cane sugar (C_(12)H_(22)O_(11)) is dissolved in 1000 g of water, the solution will freeze at

The molal freezing point constant of water is 1.86 K m^(-1) . If 342 g of cane sugar (C_(12)H_(22)O_(11)) is dissolved in 1000 g of water, the solution will freeze at

The molal freezing point constant of water is " 1.86 Km"^(-1) . If 342 g of cane sugar (C_(12)H_(22)O_(11)) is dissolved in 1000 g of water, the solution will freeze at

The molar freezing point constant for water is 1.86 ^@C / molal . If 342 gm of canesugar (C_(12)H_(22)O_(11)) are dissolved in 1000 gm of water, the solution will freeze at

The molar freezing point constant of water is 1.86 K molality^-1 . If 342 g of cane sugar ( C_12H_22O_11 ) are dissolved in 1000 g of water, the solution will freeze at:

A solution containing 34.2 g of cane sugar (C_(12)H_(22)O_(11)) dissolved in 500 cm3 of water froze at - 0.374°C. Calculate the freezing point depression constant of water.