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Explain how crossed E and B fields serve...

Explain how crossed E and B fields serve as velocity selector.

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Explain velocity of charge in combined electric and magnetic field in reference to velocity selector.

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Assertion (A),If electrons travel undefeccted by the electric field E and magnetic field B then the velocity of electrons is given by V=e/b . Reason (R ) : When both electric and magnetic field are applied simultaneously on electron beam. If force due to electric field is equal and opposite to force due to magnetic field then they travel undeflected.

In a velocity selector , the intensity of the electric field is 3 xx 10^(4) V/m and the strength of the magnetic field is 0.015 Wb//m^2 . The speed of the charged particles which pass undeflected through the velocity selector is

In a region of crossed fields as shown, the strength of electric field is E and that of magnetic field is B. Three positively charged particles with speeds V_(1), V_(2) and V_(3) are projected and their paths are shown. From this it implies that

In a region of crossed fields as shown, the strength of electric field is E and that of magnetic field is B. Three positively charged particles with speeds V_(1), V_(2) and V_(3) are projected and their paths are shown. From this it implies that

(a) An e.m. wave is travelling in a medium with a velocity vecv=vhati .Draw a sketch showing the propagation of the e.m. wave, indicating the direction of the oscillating electric and magentic fields. (b) How are the magnitudes of the electric and magnetic fields related to the velocity of the e.m. wave?

In Bainbridge mass spectograph a potential difference of 1000 V is applied between two plates distant 1 cm apart and magnetic field in B = 1T . The velocity of unflected positive ions in m//s from the velocity selector is