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For the reaction 2HI(g)hArr H(2)(g)+I(...

For the reaction
`2HI(g)hArr H_(2)(g)+I_(2)(g)`. The value of `K_(c)` is 4. If 2 mol of `H_(2)," 2 mol of "I_(2)` and 2 mol of HI are present in one litre container then moles of `I_(2)` present at equilibrium is :

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For the reaction 2HI(g)hArr H_(2)(g)+I_(2)(g) . The value of K_(c) is 4. If 2 moles of H_(2)," 2 moles of "I_(2) and 2 moles of HI are present in one litre container then moles of I_(2) present at equilibrium is :

For the reaction 2HI(g)hArr H_(2)(g)+I_(2)(g) . The value of K_(c) is 4. If 2 moles of H_(2)," 2 moles of "I_(2) and 2 moles of HI are present in one litre container then moles of I_(2) present at equilibrium is :

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The value of K_(c) for the reaction: H_(2)(g)+I_(2)(g) hArr 2HI (g) is 48 at 773 K. If one mole of H_(2) , one mole of I_(2) and three moles of HI are taken in a 1L falsk, find the concentrations of I_(2) and HI at equilibrium at 773 K.

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The value of K_(c) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) is 64 at 773K . If one "mole" of H_(2) , one mole of I_(2) , and three moles of HI are taken in a 1 L flask, find the concentrations of I_(2) and HI at equilibrium at 773 K .

The value of K_(c) for the reaction: H_(2)(g)+I_(2)(g) hArr 2HI (g) is 48 at 773 K. If one mole of H_(2) , one mole of I_(2) and three moles of HI are taken in a 1L falsk, find the concentrations of I_(2) and HI at equilibrium at 773 K.

For reaction H_(2)(g) +I_(2)(g) hArr 2HI (g) The value of K_(p) changes with

The value of K_(c) for the reaction : H_(2)(g)+I_(2)(g)hArr 2HI(g) is 45.9 at 773 K. If one mole of H_(2) , two mole of I_(2) and three moles of HI are taken in a 1.0 L flask, the concentrations of HI at equilibrium at 773 K.