The centre of a square ABCD is at z=0, A is `z_(1)`. Then, the centroid of `/_\ABC` is (where, `i=sqrt(-1)`)

The center of a square is at z=0. A is z_(1) , then the centroid of the triangle ABC is

The centre of a square ABCD is at z_(0). If A is z_(1) ,then the centroid of the ABC is 2z_(0)-(z_(1)-z_(0))(b)(z_(0)+i((z_(1)-z_(0))/(3))(z_(0)+iz_(1))/(3) (d) (2)/(3)(z_(1)-z_(0))

The centre of a square ABCD is at z_0dot If A is z_1 , then the centroid of the ABC is 2z_0-(z_1-z_0) (b) (z_0+i((z_1-z_0)/3) (z_0+i z_1)/3 (d) 2/3(z_1-z_0)

The center of a square ABCD is at z=0. The affix of the vertex A is z_(1) . Then, the affix of the centroid of the triangle ABC is

The center of a square ABCD is at the origin and point A is reprsented by z_(1) . The centroid of triangleBCD is represented by

The center of a square ABCD is at the origin and point A is reprsented by z_(1) . The centroid of triangleBCD is represented by

If Real ((2z-1)/(z+1)) =1, then locus of z is , where z=x+iy and i=sqrt(-1)

If Real ((2z-1)/(z+1)) =1, then locus of z is , where z=x+iy and i=sqrt(-1)

If Real ((2z-1)/(z+1)) =1, then locus of z is , where z=x+iy and i=sqrt(-1)