9 balls are to placed in 9 boxes : and 5 of the balls cannot fit into 3 small boxes the number of ways of arranging one ball in each of the boxes is

9 balls are to be placed in 9 boxes and 5 of the balls cannot fit into 3 small boxes.the number of ways of arranging one ball in each of the boxes is

7balls (distinct) are to be placed in 7 boxes (distinct) and 4 of the balls can not fit into 2 small boxes.The number of ways of arranging one ball in each of the boxes is X .Let P be the probability of selected divisor in the list of divisors of X is in the Form of 4n+1 ,then find 6P (where n in N)

There are 4 balls of different colour and 4 boxes of colours the same as those of the balls. Find the number of ways to put one ball in each box so that only two balls are in boxes with respect to their colour.

Five balls are to be placed in three boxes in how many diff. ways can be placed the balls so that no box remain empty if .

There are four balls of different colors and four boxes of colors same as those of the balls. Find the number of ways in which the balls, one in each box, could be placed in such a way that a ball does not go to box of its own color.