The acceleration due to gravity _____ with an increases in height and depth.

Statement I: The acceleration due to gravity decreases with increase in height from the surface of the Earth. Statement II: The acceleration due to gravity is inversely proportional to the square of the distance from the centre of the Earth.

How does the accleration due to gravity change for the same values of height and depth?

If g_e, g_h and g_d be the acceleration due to gravity at earth’s surface, a height h and at depth d respectively . Then:

If g_e, g_h and g_d be the acceleration due to gravity at earth’s surface, a height h and at depth d respectively . Then:

IF g is the acceleration due to gravity on the earth's surface , then at a depth x acceleration due to gravity will be g (1- ( x) /( R )) - prove it . [ R is the radius of the earth ]

Acceleration due to gravity on earth changes with depth and height. Find the height at which the acceleration due to gravity is 1/4 th that at the surface of earth.

Choose the correct alternative : Acceleration due to gravity increases/decreases with increasing depth (assume the Earth to be a sphere of uniform density).