[" If "A" & "B" are two events them "],[P{(A nnbar(B))uu(bar(A)nn B)}=]

If A & B are two events then P{(A nnbar(B))uu(bar(A)nn B)}=

If A o* B are two events then P{(A nnbar(B))uu(bar(A)nn B)}=(i)P(A uu B)-P(A nn B)(ii)P(A uu B)+P(A nn B)( iii) P(A)+P(B)(iv)P(A)+P(B)+P(A nn B)

If A o*bar(B) are two non empty sets then (A nnbar(B))uu(B nnbar(A))uu(A nn B) in equal to:

If A and B are two events such that P(A nn B)=(1)/(4),P(bar(A)nnbar(B))=(1)/(5) and P(A)=P(B)=p, then p is equal to

If A and B are two independent events such that P(A nnbar(B))=(1)/(6) and P(bar(A)nn B)=(2)/(15) then find P(A) and P(B)

If A o* B are two events &P(B)!=1. Prove that P(A/bar(B))=(P(A)-P(A nn B))/(1-P(B))

If probabilities A and B are two independent events then P( A nn bar B) + P( A)P( B ) = P(A) . State true of false.

If A and B are two events such that P(A uu B)=(5)/(6),P(A nn B)=(1)/(3),P(A)=(2)/(3) then A and B are

If A and B are two events such that P(A uu B)=(5)/(6),P(A nn B)=(1)/(3),P(A)=(2)/(3), then A and B are