If `A+B+C=180^(@), " then " (cosAcosC+cos(A+B)cos(B+C))/(cosAsinC-sin(A+B)cos(B+C))` simplifies to :

If A+B+C=180^(@) " then " cos A + cos B+ cos C =

If A+B+C=180^(@) " then " cos A - cos B+ cos C =

If A+B+C=180^(@) then cos A+cos B-cos C=

If A+B+C=180^(@) then cos A+cos B-cosC=

If A+B+C=180^@ " then " cos^(@) A + cos^(2)B + cos^(2)C=

If A+B+C=180^(@) , then (cos2A+cos2B+cos2C+1)/(cos A cos B cos C)

If A,B,C are the angles of a triangle, show that, (iii) (cos A cos C + cos (A + B) cos(B + C))/(cos A sin C - sin (A + B) cos (B + C)) = cot C .

If A + B + C = 180^(@) then P.T. cos A + cos (B - C) = 2 sin B sin C

If A+B+C=180^(@) then the value of cosec A(sin B cos C+cos B sin C) is

If A + B + C =180^@ , prove that : cos^2 A+ cos^2 B-cos^2 C= 1-2 sin A sin B cos C .