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The CO in a 20.3L sample of gas was conv...

The CO in a 20.3L sample of gas was converted to `CO_(2)` by passing the gas over iodine pentoxide heated to `150^(@)C` :
`I_(2)O_(5)(s)+5CO(g)rarr5CO_(2)(g)+I_(2)(g)`
The iodine distilled at this temperature and was collected in an absorber containing 8.25mL of `0.11101M Na_(2)S_(2)O_(3)` . The excess hypo was back-titrated with `2.16mL` of `0.00947M I_(2)` solution. The milligrams of `CO` in `1L` of the original gas sample was therefore:

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The CO in a 20L sample of gas was converted to CO_2 by passing the gas over iodine pentoxide heated to 150^@C : I_2O_5(s)+5CO(g)to5CO_2(g)+I_2(g) The iodine distilled at this temperature and was collected in an absorber containing 10 mL of 0.011 M Na_2S_2O_3 .The excess hypo was back titrated with 5 mL of 0.001 M I_2 solution. What must be the milligrams of Co in 1 L of the original gas sample ?

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