Figure shows four charges `q_1,q_2,q_3,and q_4` fixed is space. Then the total flux of the electric field through a closed surface S, due to all the charges, is

Show that the electric flux through a closed surface S is q//in_0

Electric flux through a closed surface in free space enclosing a charge q is

A charge +Q is placed on middle of edge of the cube.Then electric flux through cube due to field of charge +Q is

In figure + charge is located at one of the edge of the cube. Then electric flux through cube due to + charge is + a a 0- +Q

Gauss's law and Coulomb's law , although expressed in different forms , are equivalent ways of describing the relation between charge and electric field in static conditions . Gauss's law is epsilon_(0) phi = q_(encl) ,when q(encl) is the net charge inside an imaginary closed surface called Gaussian surface. The two equations hold only when the net charge is in vaccum or air . The net flux of the electric field through the surface due to q_(3) and q_(4) is

Gauss's law and Coulomb's law , although expressed in different forms , are equivalent ways of describing the relation between charge and electric field in static conditions . Gauss's law is epsilon_(0) phi = q_(encl) ,when q(encl) is the net charge inside an imaginary closed surface called Gaussian surface. The two equations hold only when the net charge is in vaccum or air . The net flux of the electric field through the surface due to q_(3) and q_(4) is

A point charge .Q. is placed at a point inside the cone as shown. The flux due to the charge through the curved surface is given as (2 Q)/(3 epsilon_(0)) . Now another charge .Q. is placed vertically above at the same distance from the base. The flux through the curved surface due to both charges is .