A stone falls from a building and reaches the ground 2.5 seconds later. How high is the building? `(=9 .8 m//s^2) `

A body falls from the top of a building and reaches the ground 2.5 s later. How high is the building ? (Take g = 9.8 m s^(-2) )

A stone dropped from a building takes 4 s to reach the ground. The height of the building is

A ball is dropped from a building. It takes 4s to reach the ground. The height of the building is (use g = 10 m//s^(2) )

If an object is dropped from the top of a building and it reaches the ground at t = 4s, then the height of the building is (ignoring air resistance) (g=9.8ms^(-2))

A stone is thrown downwards with velocity 10 m/s from the roof of a builng and it reaches the ground with speed 40 m/s. the height of the building would be

A stone is thrown downwards with velocity 10 m/s from the roof of a builng and it reaches the ground with speed 40 m/s. the height of the building would be