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If 'v' is the velocity and 'a' is the acceleration , give an example of a physical situation for each of the following cases. (a) v != 0 , a = 0 (b) v = 0 , a != 0 (c) v > 0 , a (d) v 0

In the given circuit V_(0_1) " and " V_(0_2) are -

Derive - v = v_0 + at

The position x of a particle at time t is given by x=(V_(0))/(a)(1-e^(-at)) , where V_(0) is constant and a gt 0 . The dimensions of V_(0) and a are

The position of a particle at time t is given by the equation x(t) = V_(0)/A (1-e^(At)) V_(0) = constant and A > 0 Dimensions of V_(0) and A respectively are

The position of a particle at time t is given by the equation x(t) = V_(0)/A (1-e^(At)) V_(0) = constant and A > 0 Dimensions of V_(0) and A respectively are

The position x of a particle at time t is given by : x=(v_(0))/(a)(1-e^(-at)) where v_(0) is a constant and a>0. The dimensional formula of v_(0) and a is :

The instantaneous position of a particle is given by S(t) = V_(0) (1 - e^(-at))//a , where a and V_(0) are constants and a gt 0 . What are the dimensions of a and V_(0) ?

Slope of V_(0)-v curve is- (where V_(0)= Stopping potential and v=frequency)