On a semi-circle with `A B` as diameter, a point `C` is taken, so that `m\ (/_C A B)=30^0dot` Find `m\ (/_A C B)a n d\ m(/_A B C)`

On a semi-circle with AB as diameter,a point C is taken,so that m(/_CAB)=30^(@). Find m(/_ACB) and m(/_ABC)

In Figure, A B C is an isosceles triangle with A B=A C\ a n d\ m\ /_A B C=50^0dot Find m\ /_B D C\ a n d\ /_B E C

In Figure, A B=A C\ a n d\ /_A C D=120^0dot Find /_A

In Figure, /_A=60^0\ a n d\ /_A B C=80^0, find /_D P C\ a n d\ /_B Q C

In A B C ,\ /_A=100^0a n d\ A B=A Cdot Find /_B\ a n d\ /_C

In Figure, C\ a n d\ D are points on the semi-circle described on B A as diameter. Given m\ /_B A D=70^@\ a n d\ m\ /_D B C=30^@ . Calculate /_A B D\ a n d\ /_B D C .

In Fig.26, A B=A C\ a n d\ /_A C D=120^0dot Find /_Adot

In a A B C , if /_A=120^0a n d\ A B=A Cdot Find /_B\ a n d\ /_C

In Figure, O is the centre of the circle and the measure of arc A B C is 100^0dot Determine /_A D C\ a n d\ /_A B C

A B C D is a parallelogram in which /_A=70^0dot Compute /_B ,\ /_C\ a n d\ /_D