An `alpha`-particle with kinetic energy `K` is heading towards a stationary nucleus of atomic number `Z`. Find the distance of the closest approach.

An alpha particle with kinetic energy 10 Me V is heading toward a stationary tin nucleus of atomic number 50. Calculate the distance of closest approach (Fig . 3.23). .

An alpha particle with kinetic energy 10 Me V is heading toward a stationary tin nuclcus of atomic number 50. Calculate the distance of closest approach (Fig . 3.23). .

An alpha particle with kinetic energy 10 Me V is heading toward a stationary tin nuclcus of atomic number 50. Calculate the distance of closest approach (Fig . 3.23). .

A 5 MeV alpha particle is projected towards a stationary nucleus of atomic number 40. Calculate distance of closest approach.

An alpha -particle having energy = 10 meV collides with a nucleus of atomic number 50. The distance of the closest approach is

An alpha - particle moving with initial kinetic energy K towards a nucleus of atomic number z approaches a distance 'd' at which it reverse its direction. Obtain the expression for the distance of closest approach 'd' in terms of the kinetic energy of alpha - particle K.

An alpha - particle moving with initial kinetic energy K towards a nucleus of atomic number z approaches a distance 'd' at which it reverse its direction. Obtain the expression for the distance of closest approach 'd' in terms of the kinetic energy of alpha - particle K.

A beam of beryllium nucleus (z = 4) of kinetic energy 5.3 MeV is headed towards the nucleus of gold atom (Z = 79). What is the distance of closest approach?

An alpha -particle of kinetic energy 7.68 MeV is projected towards the nucleus of copper (Z=29). Calculate its distance of nearest approach.