" (ii) "1+i^(10)+i^(110)+i^(1000)

Prove that: (i) 1+i^(2)+i^(4)+i^(6)=0 (ii) 1+i^(10)+i^(100)+i^(1000)=2 (iii) i^(104)+i^(109)+i^(114)+i^(119)=0 (iv) 6i^(54)+5i^(37)-2i^(11)+6i^(68)=7i (v) (i^(592)+i^(590)+i^(588)+i^(586)+i^(584))/(i^(582)+i^(580)+i^(578)+i^(576)+i^(574))=-1

Prove that: (i) 1+i^(10)+i^(100)-i^(1000)=0 (ii) i^(107)+i^(112)+i^(117)+i^(122)=0 (iii) (1+i^(14)+i^(18)+i^(22)) is real number.

Simplify the following : (i) 1+ i^(5)+i^(10)+i^(15) (ii) (1+i)^(4)+(1+(1)/(i))^(4) (iii) i^(n)+i^(n+1)+i^(n+2)+i^(n+3)

Simplify the following : (i) 1+ i^(5)+i^(10)+i^(15) (ii) (1+i)^(4)+(1+(1)/(i))^(4) (iii) i^(n)+i^(n+1)+i^(n+2)+i^(n+3)

Show that Find the value of: 1+ i^10 + i^100 - i^1000 = 0

Find the values of following expressions: i^(49)+i^(68)+i^(89)+i^(110) (ii) i^(30)+i^(80)+i^(120) (iii) i^+i^2+i^3+i^4 (iv) i^5+i^(10)+i^(15) (v) (i^(592)+i^(590)+i^(586)+i^(584))/(i^(582)+i^(580)+i^(576)+i^(574)) (vi) 1+i^2+i^4+i^6+i^8+doti^(20) (vii) (1+i)^6+(1-i)^3

If n= 10, sum_(i=1)^(10) x_(i) = 60 and sum_(i=1)^(10) x_(i)^(2) = 1000 then find s.d.

Let i^(2)=-1 , then (i^(10)-1/(i^(11)))+(i^(11)-1/(i^(12)))+(i^(12)-1/(i^(13)))+(i^(13)-1/(i^(14)))+(i^(14)+1/(i^(15))) is equal to a) -1+i b) -1-i c) 1+i d) -i